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Chilukuri Sai Kartik Grade: 12
        

A particle moves in x-y plane. At time t=0, particle is at (1m,2m) and has vel.(4i+6j)m/s. At t=4sec, particle  reaches (6m,4m) and has velocity (2i+10j)m/s. In the given time interval, find:


a)Avge.Vel=?


b)Avge. Acceleration=?


c)From,given data, find avge.Speed=?

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


Total displace ment = ( (6-1)2 + ( 4-2)2 )1/2


                                            = √29  m


total time     = 4 sec


change in velocity = |(2i+10j) -(4i +6j) |  =√20


 


so avg velocity = total displacement /total time


                     =√29 /4  m/sec


avg acceleration      = change in velocity /time interval


                            = √20 /4  =√5 /2  m/sec2


since path of the particle is not know only initial and final position is known so avg speed can not be calculated with this given data




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7 years ago
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