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Chilukuri Sai Kartik Grade: 12
        

A particle starts from origin at t=0 witha vel of 8j m/s and moves in x-y plane with const.acclrtn of (4i+2j)m/s2.At the instant the particle's x-coordinate is 29m,what are


1)its y-coordinate?


2)Its speed?




 

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


for motion in x direction


Ux=0


a= 4 m/sec2


Sx= 29 m


Sx=Ux t+1/2 a t2


29 =0+1/2 * 4 * t2


t2 =29/2  ........................1


Vx= Ux +at


  Vx= 4t ......................2


Motion in y direction


Sy = Uyt+1/2 a t2


Sy =8 t +1/2 * 2* t2


    =8t +t2               Answer


put value of t from equation 1 and find Sy


Vy =Uy + at


     =8  +2t   put value of t from equation 1 and find Vy       


 


now speed at this point =( Vx2 +Vy2)1/2                 Answer




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Badiuddin


 

7 years ago
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