MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
sindhuja P Grade: 11
        

Wind blows along S-E direction with a speed of 5m/s.A plstic bag is thrown with a velocity of 5(i+2j+k) m/s from a building 10m high then the position vector of the point where the bag lends off on the earth will be(x,y and z axes respectively point along east,north and vertically up directions, the point of projection being origin)_____________

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear sindhuja


velocity of wind =5/√2 (i-j)


velocity of plastic bag =5(i+2j+k)


resultant velocity of plastic bag =5(i+2j+k) +5/√2 (i-j)


                                                           =(5+5/√2)i +(10-5/√2)j +5k


time take to reach the ground


10=5t +1/2 *10* t2


t2 +t -1=0


t=1 sec


in this time distance travel in x direction =(5+5/√2) *1 =5+5/√2


in this time distance travel in y direction =(10-5/√2) *1 =10-5/√2


so position vector  =(5+5/√2)i +(10-5/√2)j +0k





Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin


 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 551 off
USE CODE: CART20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 594 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details