Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Chilukuri Sai Kartik Grade: 12
`        A train stopping at 2 stations 4 km apart takes 4 min on the journey from one of the station to the other.Assuming that it first accelerates with uni.acceleration x and then that of uniform retardation y, prove that (1/x)+(1/y)=2`
8 years ago

## Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
```										Dear Chilukuri
let t1 is time of acceleration and s1 is distance covered in this time .v is the velocity after time t
let t2 is time of retardation and s2 is distance covered in this time  .
v2=02-2xs1
s1=v2/2x..............1
v=0+xt1
v/x=t1 ..................2

and  0=v-yt2
t2=v/y .................3
02=v2-2ys2
s2=v2/2y..............4
add 2 and 3
1/x  +1/y  =(t1+t2)/v
=4/v..........5
add 1 and 4
s1+s2 =v2/2(1/x +1/y)
4=v2/2(1/x +1/y)
or (1/x +1/y) =8/v2
put value of v from equation 5
1/x +1/y  =2

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin

```
8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details