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```				   A spring of mass m and natural length L is compressed vertically downward against the floor so that its compressed length becomes L/2 . On releasing, the spring attains its natural length, If k is the stiffness constant of the spring, then the work done by the spring on the floor is:-
(a) 0  (b)  (1/2) k L 2  (C)(1/2) k (l/2) 2   (d)k L 2

```

6 years ago

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```										Dear Sanchit Gupta
Distance moved by floor is zero
so work done is also zero
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin
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6 years ago

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