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aprojectile is projected with speed u at an angle 60 with horizantal from foot of the inclined plane. if the projectile hits the inclined plane horizontally,the range on inclined plane is
Dear akash
projectile hit the plane horizontaly ,it means it hit at its hihest point
H= u2sin260 /2g
and R =u2sin120/g
or R/2 = u2sin120/2g
tan A =H/(R/2) where A is the angel of plane
=tan60 /2
=√3/2
so range on incline plane =H/sinA
Put the value of H and SinA you will get the result
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