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`        A dog of mass 5Kg is standing on a flat boat so that he is 10m from the shore.He walks 4m on the boat towards the shore and then halts. If the mass of the boat is 20Kg, find the distance of the dog from the shore when it halts________`
8 years ago

147 Points
```										Dear sindhuja
let the x1 is the distance of center of mass of boat from the shore,and Xc.m is the distance of  center of mass of the system from the shore
Xc.m =(5*10 +20*x1)/(20+5)
=2 +(4/5)  x1
now let boat move x distance away from the shore when dog move 4m towards the shore
so new distance of boat from shore=x1 +x
new distance of dog from shore=10-4 +x=6+x
now
Xc.m ={5*(6+x) +20*(x1+x)}/(20+5)
=(30+25x +20x1)/25
=6/5 +x +4/5x1

equate both Xc.m
6/5 +x +4/5x1  =2 +(4/5)  x1
x=2-6/5
=4/5
so distance =6+4/5
=34/5

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```
8 years ago
Raunaq Mehta
39 Points
```										let the x1 is the distance of center of mass of boat from the shore,and Xc.m is the distance of  center of mass of the system from the shoreXc.m =(5*10 +20*x1)/(20+5)          =2 +(4/5)  x1now let boat move x distance away from the shore when dog move 4m towards the shoreso new distance of boat from shore=x1 +xnew distance of dog from shore=10-4 +x=6+xnow Xc.m ={5*(6+x) +20*(x1+x)}/(20+5)          =(30+25x +20x1)/25          =6/5 +x +4/5x1 equate both Xc.m6/5 +x +4/5x1 =2 +(4/5)  x1 x=2-6/5  =4/5so distance =6+4/5                 =34/5
```
one year ago
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