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`        A man weighing 80Kg is standing on a trolley weighing 320Kg. The trolley is resting on a frictionless surface. If the man starts walking on the trolley along its length at speed 1 m/s, then his relative displacement with respect to ground after 4s is_______ `
7 years ago

147 Points
```										Dear sindhu

let initial c.o.m of trolley and man  from y axis is a and b repectivily
Xc.m=(320*a +80*b)/400
at final position after 4 sec =Xc.m ={320*(a-x1) +80*(b+4-x1)}/400
so equate
{320*(a-x1) +80*(b+4-x1)}/400  =(320*a +80*b)/400
-400x1 +320 =0
x1=4/5

so 4-x1=4-4/5 =16/5

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7 years ago
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