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sindhuja P Grade: 11
`        A particle is projected vertically upward with a velocity V0 ,but due to horizontal wind the particle experiences a horizontal constant accleration of a0 m/s2 . The horizontal distance travelled by the particle in a time interval in which its velocity vector rotates by 900 is_____________.`
7 years ago

## Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
```										Dear sindhuja
Initial velocity vector =V0 j
when particle will be at max hight then it has no verticle velocity,it has velocity in the horizontal direction only.
final velocity vector =V1 i
and this will be the position where velocity vector rotates by 90 degree.
so time taken to reach highest point is
0=V0 -gt
t=V0/g
and in this time horizontal distance travelled
S=0 + 1/2 *a0*(V0/g)2
S=a0V02/2g2

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin

```
7 years ago
Shane Macguire
30 Points
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7 years ago
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