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sindhuja P Grade: 11
        

A particle is projected vertically upward with a velocity V,but due to horizontal wind the particle experiences a horizontal constant accleration of a0 m/s2 . The horizontal distance travelled by the particle in a time interval in which its velocity vector rotates by 900 is_____________.

7 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear sindhuja


Initial velocity vector =V0 j


when particle will be at max hight then it has no verticle velocity,it has velocity in the horizontal direction only.


final velocity vector =V1 i


and this will be the position where velocity vector rotates by 90 degree.


so time taken to reach highest point is 


0=V0 -gt


t=V0/g


and in this time horizontal distance travelled


S=0 + 1/2 *a0*(V0/g)2


S=a0V02/2g2





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7 years ago
Shane Macguire
30 Points
										

6150-1387_9211_soln.bmp

7 years ago
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