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ramya bhaskar Grade: 11
        

A gun of mass 'M' fires a bullet of mass 'm' with a velocity 'v' relative to the gun. The average force required to bring the gun to rest in 0.5 seconds is

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear ramya


conservation of linear momentum


let the velocity of gun is V1 wrt earth


so velocity of bullet wrt eart is v-V1


m(v-v1) =Mv1


  v1=mv/(m+M)


now distance travel by gun in 0.5 sec


0=v1-a*0.5


a= 2v1     wher a is retardation of gun


so S= v1 *0.5 -1/2 *a *(0.5)2


       =v1 /4


now from work energy theorem total work done is equal to change in kinetic energy


F.S =1/2 M *v12    -0


F.v1 /4 = 1/2 M *v12


F=2Mv1


  =2Mmv/(m+M)





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7 years ago
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