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pallavi pradeep bhardwaj Grade:
        

A particle is performing shm along x axis with amplitude 4 cm and time period 1.2sec the min time taken by particle to move from x=2 cm to x=4cm and back again is given by

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Pallavi Bhardwaj


SHM equation is given as


x=4sin(2∏/T *t)


 wher T is time period


first find out time when particle will be at x=2 cm


2=4sin(2∏/T *t1)


or    sin(2∏/T *t1) =1/2


or     2∏/T *t1     =∏/6


            t1    = T/12




now find out time when particle will be at 4 cm


you can say that it will be t2=T/4 (because 4 is at extreme position)


so time taken to reach from 2cm to 4cm is  =t2- t1


                                                               =T/4 -T/12


                                                               =T/6




so total  time taken is =2*T/6


                                =T/3





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Badiuddin



7 years ago
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