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Naina Razdan Grade: 12
`        A block of mass m is kept on a rough horizontal surface. The coeff. of static friction b/w the block and the surface is μ. The block is to be pulled by applying a force to it. What minimum force is needed to slide the block? In which direction should this force act?`
8 years ago

## Answers : (2)

Rohith Gandhi
24 Points
```										Dear Eshita,

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Eshita !!!Regards,Askiitians ExpertsRohith Gandhi P
```
8 years ago
147 Points
```										Dear Eshita

F cos θ =μ N
=μ(mg-Fsinθ)
F= μmg/(cos θ +μsinθ)
For minimum force  (cos θ +μsinθ) should be maximum
and maximum value of (cos θ +μsinθ) is √(1+μ2)
so F min =μmg/√(1+μ2)
and for the direction of force let
(cos θ +μsinθ) =√(1+μ2)(1/√(1+μ2)  cos θ  +  μ/√(1+μ2)  sinθ)
=√(1+μ2)sin(θ +φ)   wher tanφ =1/μ
so sin(θ +φ)  =1
θ +φ =pi/2
θ =pi/2 -φ
= pi/2 -tan-1(1/μ)
=tan-1(μ)

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin

```
8 years ago
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