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Naina Razdan Grade: 12
        

A block of mass m is kept on a rough horizontal surface. The coeff. of static friction b/w the block and the surface is μ. The block is to be pulled by applying a force to it. What minimum force is needed to slide the block? In which direction should this force act?

7 years ago

Answers : (2)

Rohith Gandhi
24 Points
										

Dear Eshita,


 


5945-1154_8202_pr9.jpeg


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Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
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Rohith Gandhi P

7 years ago
Badiuddin askIITians.ismu Expert
147 Points
										

Dear Eshita


 


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F cos θ =μ N


           =μ(mg-Fsinθ)


F= μmg/(cos θ +μsinθ)


For minimum force  (cos θ +μsinθ) should be maximum


and maximum value of (cos θ +μsinθ) is √(1+μ2)


so F min =μmg/√(1+μ2)


and for the direction of force let


(cos θ +μsinθ) =√(1+μ2)(1/√(1+μ2)  cos θ  +  μ/√(1+μ2)  sinθ)


                     =√(1+μ2)sin(θ +φ)   wher tanφ =1/μ


 so sin(θ +φ)  =1


θ +φ =pi/2


θ =pi/2 -φ


    = pi/2 -tan-1(1/μ)


     =tan-1(μ)





Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin


 

7 years ago
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