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M. Sai Suchandan Reddy Grade: 11
        

A square of side 4 units is divided into four equal squares. the square portion ABCH is removed and placed over HCDE. What is the new centre of mass of the system. The orginal body thickness and density is uniform

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear M.Sai


 


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mass is not moved along the x axix so for new center of mass x co ordinate will remain same as earlier


and for y co ordinate of new center of mass


let mass of each part is m ,center of mass of each part of square  lies at their center


length of each side of small square is 2 unit


 


Y= [ m*1 +m*(-1) +m*(-1) +m*(-1)]/(m+m+m+m)


   =-1/2


so new center of mass (0,-1/2)


 





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Badiuddin

7 years ago
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