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tushar a Grade: 11
        a uniform rod of length l,hinged at lower end is free to rotate in the vertical plane.if the rod is held vertically in the beginning and then released,the angular acceleration of the rod when it makes and angle 45 deg. with horizontal is?
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear tushar


When it makes 45 degree with the horizontal then at this position torque acting on rod is =mgl/2 cos45


                                                                                                                             =mgl/2√2


We know that


Torque=moment of inertia * angular acceleration


mgl/2√2  =ml2/3  * angular acceleration         where m is the mass of rod


angular acceleration =3g/2√2 l





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7 years ago
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