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2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is? please solve the above question with proper explaination.

anurag bhattacharjee

13 Years agoGrade Upto college level

3 Answers

sanatan sharma

13 Years ago

draw the fbd of the system , write eqn of motion and obtain the acceleration of the bodies

let us assumw it comes out as a

now acceleration of the centre of mass will be given by

= (m₁a-m₂a)/(m₁+m₂)

negative sign because of the oppositedly directed accⁿof the two bodies

somy chaturvedi

Approved Tutor Answer13 Years ago

ans is [n-1/n+1]^2*g in downwad direction. if im right then like it , i will give the solution

somy chaturvedi

13 Years ago

solution

find acc. of both the blocks and put those in Acm=m1A1+m2aA2/m1+m2 with signs!!!!!!!! [very important].

thanxxx

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2 particles bearing mass in the ratio n:1 are interconnected by a light inextensible string that passes over a smooth pulley.If the system is released,then the acceleration of the centre of mass of the system is? please solve the above question with proper explaination.

anurag bhattacharjee

3 Answers

sanatan sharma

somy chaturvedi

somy chaturvedi

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