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`        A heavy smooth chain of mass  'm' / length and total length 'L' hanging from  smooth table edge.  The length of chain  on table is 'x''.  The height of table top from ground is 'H'. If the motion starts from rest (t=0.0 sec) at what time the entire chain will descend on the ground. `
8 years ago

23 Points
```										Dear Bhaskar,

We know the equation of motion as S = u + (1/2)a* t^2

Now the center of mass of the hanging part is at its midpiont and hence it is at height of
H-[(L-x)/2] from the ground.

And
u(initial velocity)=0
a= g   (acceleration due to gravity) , S=H-[(L-x)/2]
Thus we would get time t= squareroot of{[(2*H)-(L-x)]/g}  seconds
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```
8 years ago
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