Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 700 off


A heavy smooth chain of mass  'm' / length and total length 'L' hanging from  smooth table edge.  The length of chain  on table is 'x''.  The height of table top from ground is 'H'. If the motion starts from rest (t=0.0 sec) at what time the entire chain will descend on the ground. 

6 years ago


Answers : (1)

										Dear Bhaskar,

We know the equation of motion as S = u + (1/2)a* t^2

Now the center of mass of the hanging part is at its midpiont and hence it is at height of
H-[(L-x)/2] from the ground.

u(initial velocity)=0
a= g (acceleration due to gravity) , S=H-[(L-x)/2]
Thus we would get time t= squareroot of{[(2*H)-(L-x)]/g} seconds
Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.

All the best STUDENT NAME !!!


Askiitians Experts
Adapa Bharath
6 years ago

Post Your Answer

Other Related Questions on Mechanics

In a horizontal circular motion is mg taken into consideration?
Well , in horizontal motion most of the times force mg is balanced by normal reaction. This normal reaction is mostly perpendicular to centripetal force so it doesnt play any role. But if...
Manas Shukla 10 days ago
Yes it is taken into consideration. All the forces acting on the body are taken into consideration when solving any type of problem unless stated otherwise.
Manas Shukla 13 days ago
So do you mean that mg is always taken into consideration? Both in vertical and horizontal circular motions???
Arin Som 12 days ago
If a cycle wheel of radius 4 m completes one revolution in two seconds, then acceleration of a point on the cycle wheel will be-(1)π^2m/s^2(2)2π^2m/s^2(3)4π^2m/s^2(4)8π^2m/s^2
angular velocity would be: w = theta/time = 2*pi/2 = pi rad accln. = w^R = > pi^2 * 4 = 4*pi^2 m/s^2.
2017 years ago
a smooth rod of length kept inside a trolly at an angle theeta .whst should be the acceleration a of
Saurabh Kumar 2 months ago
@ eswar your question seems incomplete , so, kindly retype the question and post it again . we cannot find out the acceleration if we knows tye angle of inclination and there will be more...
Umakant biswal 2 months ago
The sum of magnitudes of two forces acting at a point is 16N. If the resultant force is 8N and its direction is perpendicular to smaller force,then the forces are:- (A)6N and 10N, (B)8N and...
Let the force be A and B, then the given condittions are: |A| + |B| = 16.......................(1) and |A|^2 + |B|^2 + 2ABcosthetha = 64..........................(2) and let B be the...
Vikas TU 3 months ago
A(vector)+B(vector)=R(vector) |A|+|B|=16 Since resultant is perpendicular to smaller force R*R+A*A=B*B (Traingle Law of Addition and PYTHAGORES theor m) 64+ A*A=B*B Option a satisfies this...
Atin Vikram Singh 3 months ago
Why is it not possible to apply Gauss Theorem for a FINITE straight wire?
It is not that we 'need' to use an infinite wire or plane. For example, I am sure there must be problems in the N.C.E.R.T. textbooks where you use a finite charged wire to calculate the...
Vikas TU 4 months ago
I think your question is not clear. Yes it is possible to apply gauss theorem for a finite wire.. Apply it like you do to a sphere or any other body.
Kaushàl 4 months ago
In river crossing problems please tell me all the conditions when the boat will not be able to cross the the river.
if the boat is always rowed against the flow of river it would find difficulties to cross the river. From the formulae: shortest tme it would take to cross the river is=> t = l/vcosthetha...
Vikas TU 2 months ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 650 off

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 700 off

More Questions On Mechanics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details