A body freely falling from a tower covers a distance of S=h/2 in the last second of its motion.the height of tower is?
Approved Tutor Answer14 Years agowe have the formula - S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND . ]so using the formula ------h/2 = u + a/2(2t-1)h/10 = 2t-1 { u=0 & a=10}t = h+10/20so, total time = h+10/20now by formula = h=ut + 1/2at^2, (u=0 a=10)h=h^2+100+20h/80
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 10 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
