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```				   two blocks A and B of mass ma and mb respectivly are kept in contact on a frictionless table .the experimenter pushes the block A from behind so that the blocks accelerate if the block A exerts a force F on the block B .what is the force exerted by the experimenter on A ?
KINDLY SEND ME ANS FR THIS QUESTION WITH F.B.D
```

6 years ago

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```										Force acting on B = FLet Fext be the force exerted by the personTherefore the acceleration of the system Fext=( Ma+Mb)A     -------------1Acceleration is common for both the blocks.Now, the force on B by A = F= Mb * AA=F/Mb --------- 2 Sub 2 in 1 Fext =(Ma+Mb)F / Mb
```
2 years ago

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