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chanakya rock ing Grade: 12
        

two blocks A and B of mass ma and mb respectivly are kept in contact on a frictionless table .the experimenter pushes the block A from behind so that the blocks accelerate if the block A exerts a force F on the block B .what is the force exerted by the experimenter on A ?      


KINDLY SEND ME ANS FR THIS QUESTION WITH F.B.D

7 years ago

Answers : (1)

Abhijith A Nair
37 Points
										
Force acting on B = F
Let Fext be the force exerted by the person
Therefore the acceleration of the system Fext=( Ma+Mb)A     -------------1
Acceleration is common for both the blocks.
Now, the force on B by A = F= Mb * A
A=F/Mb --------- 2 
Sub 2 in 1 
Fext =(Ma+Mb)F / Mb
 
 
 
3 years ago
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