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Divya Thakur Grade: 12
        

The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-

8 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Hi Divya Thakur


3t=(3x)^1/2 + 6


simplify the expression


x=(1/3)(3t-6)^2.........(1)


for velocity diffrentiate


v=dx/dt=(2/3)(3t-6)*3


                =6t-12


for v=0


  6t-12=0


    or t=2


put value of t in equation 1


x=0


for t<2 motion is not define


motion is just started after t>=2


at this point displacement as well as velocity is zero





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Badiuddin





8 years ago
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