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`        The relation 3t=(3x)^1/2 + 6 describes the displacement of a particle in one direction where x is in metres and t is in seconds.The displacement when the velocity is zero is:-`
8 years ago

147 Points
```										Hi Divya Thakur
3t=(3x)^1/2 + 6
simplify the expression
x=(1/3)(3t-6)^2.........(1)
for velocity diffrentiate
v=dx/dt=(2/3)(3t-6)*3
=6t-12
for v=0
6t-12=0
or t=2
put value of t in equation 1
x=0
for t<2 motion is not define
motion is just started after t>=2
at this point displacement as well as velocity is zero

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8 years ago
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