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rohan bhatia Grade: 11
        

The time taken by a body to slide down a rough 45 degrees inclined plane is twice that required to slide down a smooth 45 degrees inclined plane.the coefficent of friction between the object and rough plane is given by :


a. 1/3


b. 3/4


c. root 3/4


d. root 4/3


rply pls...

8 years ago

Answers : (3)

Badiuddin askIITians.ismu Expert
147 Points
										

hi rohan bhatia


 



 


5107-2379_7662_untitled.JPG


 


accelarion along the downward direction of wedge


 a1=(mgsin45-μmgcos45)/m


    =(1-μ)g/√2


let total time taken is t


s=0*t +.5(a1)t^2


 when wedge is frictionles


then acceleration


a2=g/√2


s=0*t/2 +.5(a2)*(t/2)^2


equate both value of s


μ=3/4






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Badiuddin

8 years ago
manoj jangra
8 Points
										

hey ans is 3/4


when you compare


let x be length of the wedge


X = 1/2 gsinθ t2           for smooth plane


X = 1/2 (gsinθ-μcosθ)4t2    foe rough plane


you will get ams 3/4

8 years ago
rohan bhatia
18 Points
										

thank u very much sir for solving my problems.


q. a block of mass m is resting on a wedge of angle θ with what minimum acceleration a should the wedge move so that the mass m falls freely ?

8 years ago
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