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```        The time taken by a body to slide down a rough 45 degrees inclined plane is twice that required to slide down a smooth 45 degrees inclined plane.the coefficent of friction between the object and rough plane is given by :
a. 1/3
b. 3/4
c. root 3/4
d. root 4/3
rply pls...```
8 years ago

147 Points
```										hi rohan bhatia

accelarion along the downward direction of wedge
a1=(mgsin45-μmgcos45)/m
=(1-μ)g/√2
let total time taken is t
s=0*t +.5(a1)t^2
when wedge is frictionles
then acceleration
a2=g/√2
s=0*t/2 +.5(a2)*(t/2)^2
equate both value of s
μ=3/4

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.  All the best Rohan.  Regards, Askiitians Experts Badiuddin
```
8 years ago
manoj jangra
8 Points
```										hey ans is 3/4
when you compare
let x be length of the wedge
X = 1/2 gsinθ t2           for smooth plane
X = 1/2 (gsinθ-μcosθ)4t2    foe rough plane
you will get ams 3/4
```
8 years ago
rohan bhatia
18 Points
```										thank u very much sir for solving my problems.
q. a block of mass m is resting on a wedge of angle θ with what minimum acceleration a should the wedge move so that the mass m falls freely ?
```
8 years ago
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