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`        WHAT Is workdone in displacing a block on a smooth surface under the action of a constant force and hence under a cons acceln`
8 years ago

bibhash jha
15 Points
```

Let us take a ball that can slide along a frictionless wire, stretched along the horizontal X-axis. A constant force directed at an angle.
f to the wire, accelerates the bead along the wire. According to Newton's second law
Fx = max ______(1)
As the ball moves through a displacement 'd', the force changes the ball's velocity from an initial value  to another value. As is constant,  acceleration 'a' is also constant.
According to equation of motion
v2 = v02 + 2 axd ______(2)
Substituting (1) in (2), we get

Hence, the work done by the force on the ball is equal to the energy transfer. Work done due to the force is W = Fx d.
Therefore, to calculate work, we have to use only the force component along the object's displacement.

W = Fx d.

=
This is the work done by a constant force (i.e., the magnitude and the direction of the force do not change.).
Work is the energy transferred to or from an object by means of a force acting on the object. Energy transferred to the object is positive work and energy transferred from the object is negative work.

```
8 years ago
24 Points
```										Since the surface is smooth and it is assumed to be horizontal, there fore there wont be any work done.

For more details , please post your question in a little more details

regards,
Rajat
```
8 years ago
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