A fighter plane is pulling out for a dive at 900 km/hr in a vertical circle of radius 2 km. Its mass is 5000 kg. ind the force exerted by the air on it at the lowest point.....and PLS EXPLAIN HOW???

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Jitender Pal 2 months ago
 
Sol. γ = 1.4, T base 1 = 20°C = 293 k, P base 1 = 2 atm, p base 2 = 1 atm We know for adiabatic process, P base 1^1-γ * T base 1^γ = P base 2^1-γ * T base 2^γ or (2)^1-1.4 * (293)^1.4 =...
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Navjyot Kalra 2 months ago
At what separation should two equal charge, 1.0 C each, be placed so that the force between them equals the weight of a 50 kg person?
 
 
a 50 kg person exerts the force, F=mg=500 newtons assuming g=10 m/s(square). So, so nearly 4.24 kilometres Thanks and Regards Apoorva Arora IIT Roorkee askIITians Faculty
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Apoorva Arora 2 months ago
 
a 50 kg person exerts the force, F=mg=500 newtons assuming g=10 m/s(square). So, so nearly 4.24 kilometres Thanks and Regards Apoorva Arora IIT Roorkee askIITians Faculty
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Apoorva Arora 2 months ago
 
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