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Let T and H be the total time of flight and height respectively.
Then H = 0.5 * g * T^2
Let v m/s be the velocity of the particle at the beginning of last 2 second.
v = g*(T-2)
according to the problem, 176.4 = v*2 + 0.5 * g * 2^2
= 4gT -2g
=> T = (176.4 + 2*9.8)/(4*9.8)
= 5
Hence H = 0.5 * 9.8 * 25 = 122.5
let u be the vel. before the 2 sec. then.........
s=176.4 a=9.9 t=2s
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