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`        water rises in the height of 10 cm in capillry tube and mercury falls to a depth of 3.112 cm in the same capillary tube If the density of mercury is 13.6gm/cc and the angle of contact for mercury is 135 degree then ratio surface tension of water and mercury is `
8 years ago

8 Points
```										Let a liquid of density ρ rise a height h in a capillary of raduis r, then we can write
hrρg = 2Tcosθ
where T is surface tension of that liquid and θ is angle of contact.
Let Tm and Tw be the surface tension of water and mercury.
Tm/Tw = [(3.112 * 13.6)/(10 * 1)] * [cosθw / cos(1350)]                (θw is the angle of contact of water)
= 5.98*cosθw

```
8 years ago
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