Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Vinay Arya Grade: 12

A particle A moving with a constant velocity of 10m/sec. Another particle B is moving
    with a constant but unknown velocity. At an instant, the line joining A and B makes an
    angle of 30 degree with velocity of A .Find the minimum possible magnitude of
    velocity of B. If they collide after some time.


7 years ago

Answers : (1)

askIITianexpert IITDelhi
8 Points

Let VB makes angle 'x' with the line joining A & B.Then component of both velocities perpendicular to line AB must be equal if they are to meet(collide).

VB Sinx = VA Sin(30degree) = 10*.866 = 8.66

VB to be min. Sinx must be max. as their product is a constant.So max(Sinx)=1

VB = 8.66 m/s

Here it simply uses the fact that minimum distance of a point from a given line is perpendicular from that point to that line. 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details