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anmol jain Grade: 11
        

A particle mover along the parabolic path x=y2 + 2y + 2 in such a way that the y-component of velocity vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-

7 years ago

Answers : (1)

Pratham Ashish
17 Points
										

hi,


parabolic path x=y2 + 2y + 2


differentiate w,r,t, t


     dx/dt = 2y dy/dt + 2 dy/dt


      Vx =  2 y Vy   + 2 Vy 


      Vx = 10y   + 10 , again differentiating


    Ax =  10 dy/dt 


   Ax =  50 m/sec^2 


 total Accl. = √ (Ax)^2 + (Ay)^2


            Ay = 0 & Ax = 50 m/ sec^2


   total accl. = 50 m/sec^2

7 years ago
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