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anmol jain Grade: 11
`        A particle mover along the parabolic path x=y2 + 2y + 2 in such a way that the y-component of velocity  vector remains 5 m/s during the motion.The magnitude of acceleration of the particle is-`
8 years ago

## Answers : (1)

Pratham Ashish
17 Points
```										hi,
parabolic path x=y2 + 2y + 2
differentiate w,r,t, t
dx/dt = 2y dy/dt + 2 dy/dt
Vx =  2 y Vy   + 2 Vy
Vx = 10y   + 10 , again differentiating
Ax =  10 dy/dt
Ax =  50 m/sec^2
total Accl. = √ (Ax)^2 + (Ay)^2
Ay = 0 & Ax = 50 m/ sec^2
total accl. = 50 m/sec^2
```
8 years ago
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