2 Answers
Ashwin Muralidharan IIT Madras
Approved Tutor Answer14 Years agoHi Rajat,
As Momentum = MxV, means when momentum is increased by 50%, velocity is increased by 50%
So if v1 was the intial velocity. Now v2 = 1.5V is the final Velocity.
Initial KE = (1/2m)v12 = k1
Final KE = (1/2m)v22 = k2
k2/k1 = v22/v12 = 1.52 = 2.25
Hence the percentage increase in KE = (2.25-1)*100% = 125%
Hope that helps.
All the best,
Regards,
Ashwin (IIT Madras).
suchita undare
let the momemtum be p
inc by 50% i.e p+p/2=3p/2
K.Ei = P2/2m K.Ef = (3P/2)2/2m=9P2/8m
change in K.E = 5P2/8m
% inc =(change in K.E/initial K.E)multiplied by 100=75%
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