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ANKUR GUPTA Grade: 12
        

A boy standing on a long railroad car throws a ball staight upwards.The car is moving on the horizontal road with an acceleration of 1m/s2 and the projection velocity in the vertical direction is 9.8m/s. How far behind the boy will the ball fall on the car?

7 years ago

Answers : (1)

Pratham Ashish
17 Points
										

hi,


till the time , ball is in the hand of bo , it will have same velocity & accl.  of car. & after it is thrown , it will continue in the horizontal velocity with accl. zero , which it has just before leaving the car


let , the velocity of car at the moment of throwing of ball = u


time taken by ball to come back again on the ground  =  2(vertical velo.)/g


                                                                            = 2 sec


during this time distance travelled by ball,  Sb = ut


during this time  distance travelled by the car Sc =  ut + 1/2 a t^2


it shows that ball will fall at a distance   1/2 a t^2 behind the boy


             1/2 a t^2 = 1/2 *1 * (2)^2


                            = 2 m.


 


 


 


 

7 years ago
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