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Grade 12Mechanics

an 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. if the engine exerts a force of 40,000 N and track offers a frictional force of 5000 N, then calculate the acceleration of the train.

Profile image of Vedanshu kumar
14 Years agoGrade 12
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To find the acceleration of the train, we first need to understand the forces acting on the system. The engine is pulling the train with a force of 40,000 N, while the frictional force opposing this motion is 5,000 N. We can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

Step 1: Calculate the Total Mass of the Train

The total mass of the train includes the mass of the engine and the mass of the wagons. The engine has a mass of 8,000 kg, and there are 5 wagons, each weighing 2,000 kg. We can calculate the total mass as follows:

  • Mass of the engine = 8,000 kg
  • Mass of one wagon = 2,000 kg
  • Number of wagons = 5
  • Total mass of wagons = 2,000 kg × 5 = 10,000 kg

Now, adding the mass of the engine and the total mass of the wagons gives us:

Total mass = Mass of engine + Total mass of wagons

Total mass = 8,000 kg + 10,000 kg = 18,000 kg

Step 2: Determine the Net Force Acting on the Train

The net force can be calculated by subtracting the frictional force from the force exerted by the engine:

Net force = Force exerted by engine - Frictional force

Net force = 40,000 N - 5,000 N = 35,000 N

Step 3: Calculate the Acceleration

Now that we have the net force and the total mass, we can find the acceleration using Newton's second law:

Acceleration (a) = Net force / Total mass

a = 35,000 N / 18,000 kg

Calculating this gives:

a ≈ 1.94 m/s²

Final Result

The acceleration of the train is approximately 1.94 m/s². This means that for every second that the engine pulls the train, its speed increases by about 1.94 meters per second, assuming the forces remain constant.