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Saurabh tiwari Grade: 12
        4429-936_5946_untitled2.jpg

the min. value of µ b/w the two blocks for no slipping is


a) F/mg
b) F/3mg
c) 2F/3mg
d) 4f/3mg
8 years ago

Answers : (4)

Pratham Ashish
17 Points
										

hi ,


in this question poin to consider is that , block 2m is not involed in any type of motion, it wil remain unmoved . so for no slipping  block m should also be at rest


 consider block m,


  net force on it should be zero,


 T - μmg = 0


T = F ,so


μ =  F /mg , it will be its min. value (a)

8 years ago
Saurabh tiwari
18 Points
										no! ans is not correct!
										
8 years ago
Pratham Ashish
17 Points
										

Hi,


 


Sorry for that,


 


actually I didn't consider the other block 


 


if see in the fig ,


 


4490-992_4788_fig.jpg


the max accelaration of the combined system of both block =  F/3m


 


now we hav to find the u for this condition


total horz. force on the block 2 =>   umg - F =m*F/3m =F/3


 


                                          =>umg = 4F/3


 


                                         =>u(min.)=4F/3mg


 


minimum u value ensure no slipping at all,  maens that the both block will move together for that given  value of FORCE


 


I really appreciate ur move bcz of  which i cud correct my mistake


 


ENJOY the  solution

8 years ago
yudhvir maan
18 Points
										

700_24487_scan0001.jpg

6 years ago
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