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```
the min. value of µ b/w the two blocks for no slipping is

a) F/mg
b) F/3mg
c) 2F/3mg
d) 4f/3mg```
8 years ago

Pratham Ashish
17 Points
```										hi ,
in this question poin to consider is that , block 2m is not involed in any type of motion, it wil remain unmoved . so for no slipping  block m should also be at rest
consider block m,
net force on it should be zero,
T - μmg = 0
T = F ,so
μ =  F /mg , it will be its min. value (a)
```
8 years ago
Saurabh tiwari
18 Points
```										no! ans is not correct!
```
8 years ago
Pratham Ashish
17 Points
```										Hi,

Sorry for that,

actually I didn't consider the other block

if see in the fig ,

the max accelaration of the combined system of both block =  F/3m

now we hav to find the u for this condition
total horz. force on the block 2 =>   umg - F =m*F/3m =F/3

=>umg = 4F/3

=>u(min.)=4F/3mg

minimum u value ensure no slipping at all,  maens that the both block will move together for that given  value of FORCE

I really appreciate ur move bcz of  which i cud correct my mistake

ENJOY the  solution
```
8 years ago
yudhvir maan
18 Points
```
```
7 years ago
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