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```
Two particles a & b,each of mass m are kept stationary by applying a horizontal force F=mg on particle B as shown in fig. then

a) tanß = 2tana
b) 2T1=5T2
c) rt2T1=rt5T2
d) noe of the above```
8 years ago

Pratham Ashish
17 Points
```										hi,
at point B,
T2*cosβ = mg .....(in vertical dirxn).............[1]
T2*sinβ = mg........(in horizontal dirxn)........[2]
dividing these 2 eqns, we get
tanβ = 1 ,.i.e β = ∏/4......

now at pont A,
T1*cosα = T2*cosβ + mg........(in vertical dirxn).................[3]
=> T1*cosα = 2T2*cosβ........(using [1])
in horizontal dirxn
T1*sinα = T2*sinβ ........................[4]

dividing 4 by 3 ,we get
tanα = 0.5*tanβ
=>  2tanα = tanβ
so correct option is (a)........
```
8 years ago
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