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Saurabh tiwari Grade: 12
        4429-2436_5946_untitled.jpg

Two particles a & b,each of mass m are kept stationary by applying a horizontal force F=mg on particle B as shown in fig. then

a) tanß = 2tana
b) 2T1=5T2
c) rt2T1=rt5T2
d) noe of the above
8 years ago

Answers : (1)

Pratham Ashish
17 Points
										

hi,


at point B,


T2*cosβ = mg .....(in vertical dirxn).............[1]


T2*sinβ = mg........(in horizontal dirxn)........[2]


dividing these 2 eqns, we get


tanβ = 1 ,.i.e β = ∏/4......


 


now at pont A,


T1*cosα = T2*cosβ + mg........(in vertical dirxn).................[3]


=> T1*cosα = 2T2*cosβ........(using [1])


in horizontal dirxn


T1*sinα = T2*sinβ ........................[4]


 


dividing 4 by 3 ,we get


tanα = 0.5*tanβ


=>  2tanα = tanβ


so correct option is (a)........

8 years ago
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