A particle is projected from a point(0,1) on Y-axis aiming towards a point(4,9). It fellson ground along X-axis in 1 second. Taking g=10m/second square , and all coordinate in metres, find the X- coordinatewhere it fell
Approved Tutor Answer14 Years agotanΦ=9-1/4-0=2=perpendicular/base. ...........(1)
where Φ is angle of projection
given that time of flight is 1 second
from s=ut-1/2gt2
(-1)=usinΦ(1)-1/2(10)(1)2 final displacement is -1 when it hit the ground ok!!
usinΦ=4
then
ucosΦ=usinΦ/tanΦ=4/2=2 (from equestion (1) tanΦ=2 )
then x coordinate = VxT=(2)X(1)=2 (Vx = horizontal componant of velocity)
particle hit the ground at (2,0) OK!!!!!!!!!
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tanΦ=9-1/4-0=2=perpendicular/base. ...........(1)
where Φ is angle of projection
given that time of flight is 1 second
from s=ut-1/2gt2
(-1)=usinΦ(1)-1/2(10)(1)2 final displacement is -1 when it hit the ground ok!!
usinΦ=4
then
ucosΦ=usinΦ/tanΦ=4/2=2 (from equestion (1) tanΦ=2 )
then x coordinate = VxT=(2)X(1)=2 (Vx = horizontal componant of velocity)
particle hit the ground at (2,0)
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