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sateesh babu rayala Grade: 12
        

A BULLET IS FIRED HORIZONTALLY WITH A SPEED OF V TO GRAGE OUT A SOLID CYLINDER PLACED ON A ROUGH SURFACE. AFTER COLLISION , THE BULLET MOVED TANGENTIALLY AT THE TOP AND THE CYLINDER ROLLS WITHOUT SLIPPING. IF THE MASS OF CYLINDER IS M , RADIUS R THE ANGULAR VELOCITY OF THE CYLINDER IS

7 years ago

Answers : (2)

askIITianexpert IITDelhi
8 Points
										

Applying conservation of angular momentum about the point of contact between cylinder & rough surface taking both bullet & cylinder as system,


mV*2R=(3/2*MR2)*ω                m=mass of bullet,Moment of inertia I(about the axis passing through contact point & || to


                                                                                                      axis of cylinder)=3/2*MR2 (by applying || axis theorem)


or, ω=4/3*(m/M)*(V/R)


Note:Judicious choice of point of application eliminate frictional torque(external to the system) here.

7 years ago
sateesh babu rayala
6 Points
										

IN THE BULLET PROBLEM  WHAT ABOUT THE VELOCITY OF BULLET AFTER COLLISION AND U DID NOT TAKE BULLET ANGULAR MOMENTUM AFTER COLLISION WHY


PL POST THE ANSWER


 

7 years ago
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