MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
neeraj pawar Grade: 12
        

how to solve the ques. of contraint motion which involve block on table which is connected by pulley & another block suspended freely under gravitation connected with the same pulley!

7 years ago

Answers : (1)

pratham ashish
9 Points
										hi,

In every qn related to constrained relation u can look for the thing which remain constant.


like in this situation La = length of the string from block A to pulley


Lb = length of the string from pulley to block B

now u can look that,

La+Lb=L {total lengh of the string whicn is costant }

now differentiating the relatn, we get :

Va+Vb=0 {vel. of the bloks}

& Aa+Ab=0 {accelrn of the bolcks},


now u can further proceed for solving the problem.


all 3 eqn above r known as constrained relations.
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 551 off
USE CODE: CART20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 594 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details