Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Tushar Watts Grade: 12
```
In the arrangement shown, the apppreciable friction exisits only b/w the bodym and the wedge.The frictional coeff being equals to @. The masses of pulley and the thread are negligible. Show that the acc of body m w.r.t the horizontal surface on which the wedge slides is given by
mg / [2m+@m+M]```
8 years ago

## Answers : (1)

Pratham Ashish
17 Points
```										hi,
fbd of m

fbd of M
let the acceleration of m in horizontal direction be  a, then from fbd.
N = ma..............................(1)
the acce. of the M will also be a,
so,     T - N = Ma
T- ma = Ma .....................................(2)
from the constraint of the length of the cord,
the vertical accel. of  m  will be the same as horizontal one,
balancing the vertical forces on m ,
mg -T - @ma = ma
mg -T -ma (@+1)  =0 ......................................(3)
putting T = Ma +ma   from eq. (2)   to (3)    we get,
mg - (M+m)a - ma (@+1) = 0
(2m+ M + @m) a = mg
a = mg /(2m+ M + @m)

```
8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 551 off
USE CODE: CHEM20
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 594 off
USE CODE: CHEM20

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details