Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 560 off


A block weighing 20 N rests on a horizontal surface. The coeff of static friction b/w the block and surface is 0.04 and the coeff of kinetic friction is 0.20. How long is the friction force exerted on the bock.

7 years ago


Answers : (1)


As the Q say ,block is resting on the horizontal suraface.So unless some external horizontal force is applied on it there is no

frictional force on it.To move the block min. hor. force required would be equal to maximum static frictional force=(coeff. of st. fr.)*(normal reaction N exerted by surface on the block)

where N=weight of the block=mg

Until applied force is greater tha above block will not move.At any time frictional force on the block = force applied(upto maximum static frictional force ).

After that as block gets in motion kinetic frictional force will oppose the motion.Here again max. kin. fr. force=(coeff. of kin. fr.)*N

As applied force is already greater than this, the max. kin. fr. force is the only opposing force to the same & it will be so as long as applied force>max. kin. fr.force.Whenever it became equal or less block will stop & to get it in motion again you have to apply force>max. st. fr. force as stated above.


7 years ago

Post Your Answer

Other Related Questions on Mechanics

the moment of inertia of a solid flywheel of radius 0.1m about its axis is 0.1kgm2. a tangential force of 2 kg wt is applied through the circumference of flywheel with the help of string...
ANS: 2m/s 2 equate the torque I alpha = force * r (r = radius of wheel) 0.1*a/r = 2*10* r ( a = accelaration) therefore a=2m/s 2 ( r = 0.1m)
Adikesh Kumar 5 days ago
Solve that 21 st which is in the image..................
The answer of this easy question is A or B or C or D as the gun fire a certain speed which is constant and the acceleration acting downward
Chris Gayle 4 days ago
a ball is projected with a velocity of 40√2 m/s at an angle of 45 find the position and velocity of the ball after 2 sec
please explain further in an easier way
the 3 months ago
velocity in both x and y directions=40 m/s. For X coordinate, X=40t i.e X=40x2=80m For Y coordinate, Y=Uyt+1/2gt^2 i.e. Y=40x2-1/2x10x4=60m Position of ball after 2 sec= (80,60) Velocity in ...
Prabhjot Singh 3 months ago
how to study this lesson and how to make my self prepared with this topic
@SHIVA this chapter completely depends upon the assumption capacity , frst of all read it from ncert , your 30 percent of concept will be cleared from that only , after that take out...
Umakant biswal 3 months ago
what is first law of thermodynamics??
neither created nor destroyed but it tansfer to one form to another form
Gavvala Ganesh one year ago
Dear Ganesh, Please do not paste the same answer again and again. Also, paste complete answer in one attempt so that questioner does not get mails on your each and every answer. This...
Forum Team one year ago
The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic systems. The law of conservation of energy states that the total energy of an...
KUNCHAM SAMPATH one year ago
what is the difference between current amplification factor and current gain?[ce and cb]
@ nayana The current amplification factor is besically the ratio of the output current to the input current when its passing through an electrical devices . so, it gives us the amount of...
Umakant biswal 3 months ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 520 off

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 560 off

More Questions On Mechanics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details