Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        A TRAIN IS MOVING TOWARDS NORTH AT ONE PLACE IT TURNS TOWARDS NORTH EAST HERE WE OBSERVE THAT THE RADIUS OF CURVATURE OF OUTER RAIL WILL BE GREATER THAN THAT OF INNER RAIL WHY???
PLS EXPLAIN```
8 years ago

Ramesh V
70 Points
```										Dear friend,
This is because the wheels are preferably fixed to the axle and are therefore forced to turn at the same peripheral rotational velocity, this system force the wheel positioned radially inwardly during a turn to slip or slide on the rail, since it travels a shorter distance through a turn than the radially outermost wheel.
The maximum speed of a train on curved track is determined by the following formula:
Vmax = [ (Ea +3) /0.0007d ]1/2  where  Ea is the height in inches that the outside rail is "superelevated" above the inside rail on a curve and d is the degree of curvature in degrees per 100 feet (30 m). Vmax is in miles per hour.
The maximum value of cant (the height of the outer rail above the inner rail) for a standard gauge railway is about 6 inches (150 mm).
......
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Naga Ramesh
IIT Kgp - 2005 batch
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 220 off
USE CODE: Neerajwin
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 237 off
USE CODE: Neerajwin