Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A driver applies brakes to the vehicle on seeing traffic signal 400 m ahead .At time of applying the brakes vehicle was moving with 15m/s and then starts retarding with 0.3 m/s^2 .The distance of vehicle after 1 min from traffic light A : 25 mB : 375mC : 360mD ; 40m`
8 years ago

Ramesh V
70 Points
```										The equations of motion are:
Using relation V2 - u2 = 2*a*S
and Using relation V - U = a*t     V:final vel.  U: initial vel.  a:accln  S:distance travelled
The distance travelled before car comes to rest is V=0, U = 15,a=-0.3
S=225/0.6 =375mts
The car comes to rest even before reaching traffic signal.
It comes to rest at 25m ahead traffic signal.
The time taken by car to come to rest is : V/a = 15/0.3 = 50 sec
In 50 seconds car comes to rest
so after 1 min,also car stays 25m ahead of traffic post
option A
```
8 years ago
8 Points
```										Distance travelled by vehicle in 1 min.(=60 sec.) after applying brakes=15*60-(0.3)*602 = -180mtrs.(s=ut+1/2at2)

(-ve) value above indicates that vehicle must've stopped due to brake action in less than 1 min.
So using,
v2=u2+2as;s=(15)2 /(2*0.3)=375m
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details