Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A particle moves along the X-axis as x = u(t - 2s) + a(t - 2s)^2. What is true?..................a) the initial velocity is u. b) the acc. is a. c) the acc. is 2a. d) at t = 2s, particle is at origin. Will the asnwer be a,c and d? `
8 years ago

Mukul Tuli
18 Points
```										answer is a ,b an d
```
8 years ago
8 Points
```										yes the answer will be a c and d assuming constant acceleration.
since x is the coordinate point and particle moves only along the x axis, hence x  is the displacement of particle.
now comparing the expression with the 2nd equation of motion we can easily conclude u is the initial velocity because its the coefficient of first degree term(expressinon being a function of time shifted by 2 units).
and acceleration being 2a.
```
8 years ago
dharani bandaru
18 Points
```										I think the answer is c and d.when the given relation is differentiated once we get the velocity and when u put t=0 velocity will not be u.so "a" is wrong.again differentiate it .we will get the acceleration .put t=0 .accel. is 2a      so "b"is wrong.and "c" is correct. coming to "d" put t=0 in given relation x=0 is the answer . dat means it is at the origin.so "d" is true.
```
7 years ago
Amarjit
66 Points
```										On differentiating x with respect to t we get the equation; dx/dt= u+2a(t-2s).dx/dt is velocity and here it is in terms of t.Initial velocity is the velocity at t=0. So, on putting t=0, we get dx/dt(t=0)=        u-4as.Hence option a is not correntCorrect answer c,d.
```
2 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details