MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Balaji Venkatesh --- Grade: 12
        what is the minmum velocity of a projectile such that it touches  4 vertices of a regular hexagon??
7 years ago

Answers : (1)

AskIITians Expert PRASAD IIT Kharagpur
18 Points
										

For projectile to pass through four points A, B, C, D of a regular Hexagon of side a,


we must throw the projective from A and its fall at D passing through B and C in between.


 


for this we must have Range to be twive of maximum height,


i.e    2 * (u^2 * sin^2(@)/ (2 * g))  =  (u^2 * sin2@/ g)


@ = angle of throw.


Solving above  we get @ = arctan(2) = 63.43 degrees.


Putting aobe in any of equations of Range or height we have


u =  4.95 * (a^0.5).


a = side of hexagon.


 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 551 off
USE CODE: CART20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 594 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details