Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
bhanuveer danduboyina Grade: 12th Pass
`        The magnitude of displacement of a particle moving in a circle of radius 'a' with constant angular speed 'w' varies with time 't' as:  `
6 years ago

## Answers : (1)

vikas askiitian expert
510 Points
```										R = acos@ (i) + asin@ (j)       ................1
R is the position vector of particle at any time performing circular motion...
@ is angular displacement

w = @/t
@ = wt         ..............2
from 1 & 2
Rt = acoswt (i) + asinwt (j)          .............3
at t = 0 ,
Ro = a (i)             ..............4

displacement = Rt - Ro = a(coswt-1) (i) + a(sinwt) (j)
magnitude =[ (a2(coswt-1)2 + a2(sinwt)2]1/2
=  [2a2 - 2a2coswt]1/2
= a[2(1-coswt)]1/2

now , coswt = (1-2cos2(wt/2)) , after putting this in above eq
magnitude = 2a[cos2(wt/2)]1/2
=2acos(wt/2)
this is the required result ,

approve if u like my ans
```
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 551 off
USE CODE: CHEM20
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 594 off
USE CODE: CHEM20

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details