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`        a stone is thrown upwards with an initial speed of 10m/s. calculate the time after which it acquires the same initial speed but travels in opposite direction.`
6 years ago

510 Points
```										total time of flight is the time after which it attains same speed but in
opposite direction...
T = 2(u/g)1/2 = 2sec
```
6 years ago
iit jee
44 Points
```										let 'u' be initial velocity=10m/s.
we know that v=u-gt1(t1 is time of ascend, v=0,g=10m/s2)
t1=1 second.
during ascend u=0 and let t2 be time of descend,v=10m/s
by plugging the values in equation v=u+gt2
we get t2=1second
therefore the time after which it aquires same speed is t1+t2=2 seconds
plzzzzzzzz approve!!!!!!!!!!!!!!!
```
6 years ago
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