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let b be the angle of projection with the inclined plane whose inclination is a
then the condition for it to land perpendicular the plane is 2tan(b-a)=cota
if the projectile land on the surface horizontally(parallel to ground ) then tanb = cota+2tana
it can be easily derived from the formulas of motion on inthe inclined plane such as
x=ucos(b-a)t -(1/2)gsin(a)t^2
y= usin(b-a)t-(1/2)gcos(a)t^2
by appling the condition.
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