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`        Derive the moment of inertia of a rectangular plate having sides a and b about an axis passing through one end and perpendicular to the plate.`
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
I = integral (r^2) *dm rho = m/ab dm = rho*b*dr therefore, dI = r^2 * rho*b*dr. plugging in rho we get dI = (r^2 * m *b*dr )/ab  If you integrate this from 0 to a, you get I = (m*a^2)/3
Using perpendicular axis theorem, Iz = Ix + Iy so Iz = [m (a^2 + b^2)]/3

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6 years ago
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