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kanchana Rao Grade:
        Four particles of equal masses M move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.
6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

net force on any of particle due to remaining three = GM2 (81/2+1)/4R2


centripital force is provided by mutual gravitational force


GM2 (81/2+1)/4R2 = MV2/R


  V = [GM(81/2+1)/4R]

6 years ago
sai raghava rajeev penagamuri
14 Points
										

SQUARE ROOT OF GM/R(2(1.414)+1)/4

6 years ago
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