MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
debadutta mishra Grade: 11
        

A cat of mass 1 kg moves up  on an massless string which goes along a friction less pulley so as to just lift a block of mass 2 kg.After sometime the cat stops moving with respect to the string .The magnitude of change in cats acceleration is?

6 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
										

Dear Debadutta,


initial upward acceleration of cat=g


final acceleration=(2-1)g/(2+1)=g/3 upward


change in cat's acceleration=g-(g/3)=2g/3


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.



All the best Debadutta !!!


 



Regards,


Askiitians Experts


CHETAN MANDAYAM NAYAKAR

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 551 off
USE CODE: CHEM20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 594 off
USE CODE: CHEM20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details