Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        pls derive G=g-w2.R.cosx
with every explanation plsssss!!!!!!```
6 years ago

510 Points
```										let there is a particle at rest on the surface of earth in latitude @....  seudo force is acting on particle outwards &
real accleration due to gravity acts along the center of earth , then
Fc = seudo force = mW2r                    (r is distance of particle from center)
fg = force due to gravity = mg
net force towards center is F = (fg2 + Fc2+2fgFccos(180-@)1/2     (by vector law )

putting these values , F = m[(g2+(rW2)2 - 2grW2cos@)]1/2                  ...........1

now  F = mgeff         .................2
from 1 & 2
geff = [g2+(RW2)2 - 2grW2cos@]1/2                ..............3
now , W = 2pi/T          (T = 24hrs)
W <<<<<<<<1  so we can neglect (rw2)2 , now
geff = [g2 - 2grW2cos@]1/2
r = Rcos@            (R is radius of earth)
geff = [ g2- 2gRW2cos2@]1/2
= g[ 1 - 2RW2cos2@/g ]1/2 ,  this is similar to g[1-RW2cos2@/g]
geff = g - W2Rcos2@      ...................................4
this is the required result

```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 220 off
USE CODE: Neerajwin
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 237 off
USE CODE: Neerajwin