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somy chaturvedi Grade:
        

a small block oscillates back and forth on a smooth concave surface of radius R . find the time prriod of small oscillation


 

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

applying conservation of energy


mv2/2  = mgR(1-sin@)                 (@ is inclination with verticle )


differentiating this eq wrt time


mvdv/dt = mgRsin@d@/dt


  dv/dt = a ,  d@/dt = W


mva = mgRsin@W


for small angle sin@ is equal to @


mva = mgR@W


 now v = wR , & a = alfa(R)


alfa(algular acc) = g@/R


alfa = W2@  so


  W = (g/R)1/2


T = 2pi/W = 2pi(R/g)1/2


 

6 years ago
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