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a ring of mass m and radius r has three particles attached to the ring as shown. the center of the ring has a speed V0. the kinetic energy of the system is : (slipping is absent)
velocity of left side particle is 21/2Vo
velocity of right side particle is 21/2Vo
velocity os particle at top is 2Vo
KE of ring = 1/2( Iw2+ mVo2) = 1/2(2mVo2)
KE of particles = 1/2(2M2Vo2+M(2Vo)2+M2Vo2) = 1/2(10MVo2)
total KE = 1/2(2mVo2+ 10MVo2) = Vo2(m+5M)
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