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Ajay Kumar Grade: 11
        

a ring of mass m and radius r has three particles attached to the ring as shown. the center of the ring has a speed V0. the kinetic energy of the system is : (slipping is absent)


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6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

velocity of left  side particle is 21/2Vo


velocity of right side particle is 21/2Vo


velocity os particle at top is 2Vo


KE of ring = 1/2( Iw2+ mVo2) = 1/2(2mVo2)


KE of particles = 1/2(2M2Vo2+M(2Vo)2+M2Vo2) = 1/2(10MVo2)


total KE = 1/2(2mVo2+ 10MVo2) = Vo2(m+5M)

6 years ago
Rakesh kumar
11 Points
										velocity of left  side particle is 21/2Vovelocity of right side particle is 21/2Vovelocity os particle at top is 2VoKE of ring = 1/2( Iw2+ mVo2) = 1/2(2mVo2)KE of particles = 1/2(2M2Vo2+M(2Vo)2+M2Vo2) = 1/2(10MVo2)total KE = 1/2(2mVo2+ 10MVo2) = Vo2(m+5M)
										
one month ago
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