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`        A tank contains water on top of mercury.A cube of iron,60mm along each edge,is sitting upright in equilibrium in the liquids.Find how much of it is in each liquid.The densities of iron and mercury are 7.7g/cm3 and 13.6g/cm3 respectively`
6 years ago

419 Points
```										Dear Sohan
Suppose x1 length is in water and x2 in mercury
and x1+x2=h=60mm...............(1)
here equilibrium equation will be
Weight = total buoyant force for each medium,  W=B=Bw + Bhg...........(2)
weight=W= density of cubex volumexg= dcx(Axh)xg,   where A is h2
Bw=dw*(A*x1)*g
Bhg=dhg*(A*x2)*g
use equation 2
after cancelling terms on rhs and lhs you will get
dc*h=dw*x1+dhg*x2
put values of density
7.7h=x1+13.6x2..............(3)
solve for x1 and x2 using 1 and 3
x2=6.7h/12.6= 6.7*60/12.6 = 31.9 mm in mercury
in water=60-31.9=28.1 mm
All the best.
AKASH GOYAL

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6 years ago
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